• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

General Thoughts: Mathematics Extension 1 (6 Viewers)

Patato

New Member
Joined
Nov 5, 2009
Messages
27
Gender
Male
HSC
2011
Re: Wow, fuck that

wasn't the question find the exact value of cos-1(-1/2)??

which is pi - cos-1(1/2)
= pi - pi/3
= 2pi/3

?
 

lpodnano

5eva alone
Joined
Mar 6, 2008
Messages
1,561
Location
;)
Gender
Female
HSC
2011
Re: Wow, fuck that

yayyy. I got A=0. I kept thinking it was wrong because I kept checking over my working out. B=2 right? from memory... I think..
 

Tasha270494

Member
Joined
Jan 13, 2010
Messages
58
Gender
Female
HSC
2011
Re: Wow, fuck that

What was the total distance the particle travelled? 8?
 

friend177

Member
Joined
Aug 22, 2011
Messages
359
Gender
Male
HSC
2011
noooooo. I did that too. I took the positive time. damn
Fml I added 1:14 to 10am not minus it FML there goes 1 mark hopefully I'll still get 2/3 considering I found theright time..God bless us all
 

damo_g

Member
Joined
Oct 21, 2011
Messages
92
Gender
Male
HSC
2011
You were supposed to get a negative time???? I got the negative time and tried to figure out what was wrong but couldn't see anything so i just left it.
 

kev-is-red

Member
Joined
Oct 22, 2011
Messages
105
Gender
Male
HSC
N/A
The very last thing I did was go back and found that A = 0 and B = 2

Cheerin!
 

lpodnano

5eva alone
Joined
Mar 6, 2008
Messages
1,561
Location
;)
Gender
Female
HSC
2011
Re: Wow, fuck that

Oh shit, I think I got 4 -.-
 

Implying

Member
Joined
Mar 16, 2011
Messages
63
Gender
Male
HSC
2011
Re: Wow, fuck that

8 or 8n or something, i can't remember

i intergrated from 0 to 2pi/n for the acceleration graph, as the area under an acceleration graph is equal to displacement =/
 

Tasha270494

Member
Joined
Jan 13, 2010
Messages
58
Gender
Female
HSC
2011
Re: Wow, fuck that

8 or 8n or something, i can't remember

i intergrated from 0 to 2pi/n for the acceleration graph, as the area under an acceleration graph is equal to displacement =/
.. isn't it under a velocity-time graph?
 

Users Who Are Viewing This Thread (Users: 0, Guests: 6)

Top