Re: Australian Maths Competition 2013
if anyone is interested this is my working. Not very logical wording but w/e
the question was something like: chris and cody run a 100m race. when chris finishes, cody still has 5m left. Cody and joseph then run a 100m race, and when cody finishes, joseph still has 10m left.
Let t be the time in seconds that chris takes to finish the race.
In t seconds, Cody runs 95m.
in t/95 seconds, Cody runs 1m.
In 100t/95 seconds, Cody runs 100m. (i.e. in 20t/19 seconds, Cody runs 100m)
In 20t/19 seconds, Joseph runs 90m.
In t seconds, Joseph runs (90x19)/20 m (i.e. in t seconds, Joseph runs 85.5m)
Therefore joseph finishes 14.5m behind Chris.
