obviouslyme
Member
- Joined
- Apr 27, 2013
- Messages
- 33
- Gender
- Male
- HSC
- 2014
Hey guys, so when a question says, "Prove/show that expression x = expression y"
Can you start from RHS like this:
RHS = expression y
=...
=expression x
= LHS
Will you be penalised? Because sometimes i can't see how to work from LHS to RHS (especially when LHS is simplified and RHS is expanded). I've asked my teacher and she said, "The marker won't like it, yes you will get penalised". So i reckon that's too risky to do it in internal assessments but how about a HSC exam? Thanks!
If you don't understand what i mean, here's an example
Show that u/(u+1) = 1 - 1/(u+1)
And well i can't do it from LHS, so i go
RHS = 1 - 1/(u+1)
= (u+1) - 1 / (u+1)
= u/ (u+1)
= LHS
Also if you can, can you show me how to get from a simplified version to an expanded one? Thanks guys
Can you start from RHS like this:
RHS = expression y
=...
=expression x
= LHS
Will you be penalised? Because sometimes i can't see how to work from LHS to RHS (especially when LHS is simplified and RHS is expanded). I've asked my teacher and she said, "The marker won't like it, yes you will get penalised". So i reckon that's too risky to do it in internal assessments but how about a HSC exam? Thanks!
If you don't understand what i mean, here's an example
Show that u/(u+1) = 1 - 1/(u+1)
And well i can't do it from LHS, so i go
RHS = 1 - 1/(u+1)
= (u+1) - 1 / (u+1)
= u/ (u+1)
= LHS
Also if you can, can you show me how to get from a simplified version to an expanded one? Thanks guys