Recent content by daryl-d

geometrically tan Theta represents the gradient of a line. if the line is y -y(0) = m(x -x(0)); then m is the gradient of the line; as gradient equal rise/ run, i.e. opposite side/ adjacent = tan(theta); hence m = tan(theta); You solve the question if u know what m or theta is

They pretty much give you marks if u know what youre doing. But i understand your concern as some teachers may not like this

If you want to get good marks, don't use the textbook, For the trial exams and half yearlies Teachers usually don't put similar types of questions from recent hsc papers (except maybe for Q9 or 10). My advice is to have a go at the 1986 -1992 past papers. It helped me so much that i got 119/120...

is the travel pass also called a purple pass

can someone please tell me if this is correct: Thanks for the post below guys, i had a feeling my long divison was wrong

first use the remainder theorem, i.e. Q(1)=o, or (x-1) is a factor of Q(x) therefore: 1+p+q -5 +1 =0 p+q=3 Then using longdivision: u get Q(x) = (x^2 + 2) B(x) +R [ where R is the remainder and B(x) = x^2 +px +(q-2)] ] R= -x(5+2p) -2q +1 [now equate...

whats urs

how about no, k i'll tell u if u promise not to tell anyone else

i dunno, but i definetly didn't get 1st in the state

i dunno

and ur not that "uncle buck" dude lol

hey stop hacking out on me...........or i will start cutting u on facebook

i dont think i need the chips amelia, but thanks any way

for once amelia i cant believe i'm saying this but i totally agree with you, the highlight for me was the drive there to be honest, it was excellent

stop the hating