btw i have no clue what u did in Q13.
i was taught when u want shear stress, the area in question is the perimeter multiplied by the thickness.
hence, stress = (15x10^3)/(4x0.025x0.005)=300MPa
anyone know anything about PCD (Pitched circle diameter)? Q16e 2009 HSC has something about it and in the answers i can't seem to understand what they did or if it has anything to do with the PCD:s
i have attached both the question and solution. If anybody can explain the part of the solution on...
My understanding of this question is that the "possible solutions" have not included ∆PE, and also, i have no clue where they got there value for mass from. If you include ∆PE, and use the correct mass, you get 28.11m.
the mass can be found as we know the resistance to motion (Frictional force)...
My teacher said something quite similar in that physics scales only slightly higher than engineering studies. However, almost ever ATAR calculator considers engineering studies to scale nowhere near as good as physics which leads me to the conclusion that a teacher will make say anything to get...