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damn this guy is a mudkip lover too
You really don't need one for biomath. For metric spaces, something like Searcoid's book, supplemented by Munkres' Topology for anything not in Seacoid / for a more abstract viewpoint.
For Galois theory maybe Stewart's book is a good choice. If you want something broader/higher level you can try M.Artin's or Hungerford's or Lang's Algebra, and just check out the Galois theory part (these three books being listed in increasing order of difficulty imo). Things will be terser in those books than in Stewart though.
My recommendations aren't really suitable to find honours stuff in though, they are more about expanding your toolkit.
You generally want to look at graduate level books/papers for honours projects, and talk to potential supervisors.
Yeah I am invited, I'm working that day though so it doesn't look like I'll be able to make it.
can confirm that 2nd place was a baulko.
was surprised myself :O
okay. no worries. will do some asking around then, after results come out
yep Immortality is baulko. so was esaitchkay, tomnomnomnom, mirachel.
and just clarifying, no-one from baulko beat your original score right?
it's Immortality, isn't it?
aww yiss. I have a good idea of who it is. Can I have one guess?
so you've been beaten? :O
lol are we still going through with the bet on a baulko person beating you in BOS 4U trial after you minus 10 from your result? how the hell are we going to figure out if it had happened or not lol?
done! - i.e. I deleted it.
haha no worries! I'm not really expecting a reply - just wanted to know that you actually received it haha. I just didn't know if I sent it to the right email lol. whenever you get time could you PM or email back me with your USYD email and good luck with uni stuffs
oh and just checking - you still use your Hotmail right? :O because I emailed to that Hotmail address posted on your thread that advertises your tutoring. just letting you know
btw I emailed you, since your PM inbox was fullManaged to prove the inequality that puzzled us on Saturday
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(a+b+c)/3 is greater than or equal to the cube root of abc.
Using the fact that (x^2 + y^2 + z^2) is greater than or equal to xy + xz + yz, multiply both sides by (x+y+z).
You get a whole heap of terms on both sides which cancel out.
You're left with (x^3 + y^3 + z^3)/3 is greater than or equal to xyz.
Let a = x^3, b = y^3, c = z^3
(a + b + c)/3 is greater than or equal to cube root of abc -
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