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0.085 x (207.2 + 32.07 + (16 x 4)) = 25.77795 OMG IS THIS THE ANSWER????

We use the pbno3 moles because pbno3 and pbso4 has same mole ratio right? Or what you said just then, you always use the limiting reagent?

Ah yeah sorry

is it 0.85 times pbno3 molecular weight which gives the moles?

Acutlally sorry no wait sorry mb

because we have the c=n/v we have c and v where c is 0.5 and v is 0.065 and if you times them together you get 0.0325

to find pbs04 first find the moles for it which is 0.0325( correct me if im wrong) Then 0.0325 x molecular weight of pbso4 right?

Actually one moment

limiting reagent is 0.085? since it requires 3 moles of that to make 1 mole of also4

Desperate help please. A 100ml solution of 0.85mol/L lead nitrate is mixed with a 65ml solution of 0.5mol/L aluminium sulfate. Calculate the mass of lead sulfate you would expect to form Pb(NO3)2 + Al2(sO4)3 ---> PbSO4 + Al(NO3)3 3 1 3 2 Thats...

Can someone help me and explain in details cause ive been explained by people so many times but im still confused. A sample of fertilise contains 32.5g ammonium sulfate. What is the mass of nitrogen in this fertiliser? So i found the mole of ammonium sulfate which is 0.2421417437 then this part...

Is this still on??? :DDD