Search results

woah, where did the -16 come from?

so i got p=4 q=-44 and then i substituted a which got f(a)= 4a^3+16a^2-44a-120 how do i get to find out what a equals, since there are no like terms?

do i find out p and q by simultaneious equations? thanks ^^

The polynomial f(x) is given by f(x) = px3 + 16x2 + qx - 120, where p and q are constants. The three zeroes of f(X) are (-2), 3 and a. The value of a is? I'm not sure how to start. and what does 'zeroes' mean? How do work this out? :newburn: It was a multiple choice so the answer is...

The polynomial f(x) is given by f(x) = px3 + 16x2 + qx - 120, where p and q are constants. The three zeroes of f(X) are (-2), 3 and a. The value of a is? I'm not sure how to start. and what does 'zeroes' mean? How do work this out? :newburn: It was a multiple choice so the answer is...