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Okay, can I tell you what I did and you tell me where I went wrong? So to solve b) I wanted to find the stationary points, because I can test around the stationary points to find where y is decreasing. To do this I need to solve secx (2sec^2 x -1)=0 right? I then solved (sec x) = 0 first and...

I'm sorry can you please explain it again? I don't understand what 0 < x < 2 pi, has anything to do with pi/2 < x < 3pi/2 just because sec x is negative. Ty!

Why? I don't understand why "this can happen only when..."

I thought i interpreted it correctly though?

a) Show that d/dx(secxtanx) = secx (2sec^2 x -1) b) Hence find the values of x for which the function y = secxtanx is decreasing in the interval 0 < x < 2pi. THANKYOU!

in the interval 0 < x < 2pi

The question was secx(2sec^2 x - 1) = 0 This is actually the derivative of another equation and I have to find values for x that are decreasing. ^^

You can't cos-1 (root 2)

2sec^2 (x) -1=0 apparently x= 3pi /2 ?????how????? ty

Thanks!

How to solve : tan^2 (x) -1 = 0 (I basically have to find the stationary points but I'm not sure how to find x)

Hi! How would you find the value of this?

no....Drongoski, what's wrong with my method though?

If you have 4C1 ..the isn't it supposed to be (x^2)^3x(-3)^1?

Cool thanks! I think I understand :D

Hi guys, I've been stuck on this binomial theory question (find the coefficient of x^3) HHHNNNNGGGG what am I doing wrong? Many thanks, Frustrated girl

Hey people, Some of you have probably already ordered your jerseys for year 12 but our school is slowas so could you guys recommend some good quality and decently priced offers from any jersey committees? Thanks in advance peace out.:blink2:

Thanks dude!

Hello, How do you solve for a and b? a+ib= square root 2i Thankyouuu

Ohhhhhhh! Yes I understand now (: Z^3-1^3