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Swans premiers 2014.

Mods moving my thread it deserved a new thread

Huge News: Lance Franklin Official Signs with the Swans Just got this update on Facebook m.afl.com.au/news/2013-10-08/buddy-becomes-a-swan

Up there cazaly

\frac{3^k - 1 + 2*3^k}{2} I will write it like this \frac{1*3^k - 1 + 2*3^k}{2} And then rewrite it like this: \frac{1* 3^k + 2*3^k -1}{2} From the numerator, if we have ONE lot of 3^k and we add it to TWO lots of 3^k, isn't that the same as saying THREE lots of 3^k? \frac{3* 3^k-1}{2}...

Meant f2p ppl with p2p skills up to 5.

Wow they made all skills f2p up to level 5

Whats dis new skill divination

Superconductivity

Wanna play rs together then?

That ain your acc.

I don't understand what you are trying to say sorry but for your first question: We require to prove (for the appropriate values of k) 2+4+6+....+2k + 2(k+1) = (k+1)((k+1)+1) If you have difficulties with that, try equivalently proving: 1+2+3+....+n = \frac{n(n+1)}{2} For your second...

Yup, but not your usual standard induction equations for 3U http://www-history.mcs.st-and.ac.uk/~john/MISS.pdf http://www.geometer.org/mathcircles/indprobs.pdf

You what? What does LHS = RHS mean in that context? Make sure you are clear on each step. \mathit{Proof}:\; $Let$\; P(n)\; $be the proposition$ \;1+3+3^2+3^3+..+3^{n-1} = \frac{3^n -1}{2} \;$for all positive integers$\; n. \textsc{Base step}: $For$\; n = 1,\; $we have,$ \;$LHS$\...

Wut no, look carefully at the inequality signs and the derivative.

C (from memory -cbb flicking back)

^Troll

Not sure if troll or really in Year 7