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Thanks for your helpful hint... 'Realise Nothing'

Thanks for your comments Sy...:D I will continue to work on this....:D

How about Find the exact values of p in the equation x^2 + px + 3 = 0 if a) the roots are equal? b) the roots are reciprocals of one another?

Ah ha... Thanks heaps.. .:) Yup, I can.... :D

Thanks heaps.... Is it the same if its (k + 1)/4 Sorry... I wrote it unclear. :)

Can someone help me expand the equation and make it greater than or equal to zero? Please? Thanks in advance. :D

You need 10 units of 'Board Developed Courses' to be eligible for an ATAR ... Some Subjects are content endorsed... While others are VET subjects and only ONE VET subject counts towards an ATAR (If you happen to be doing more than one...) :D Trust this makes sense!

What site did you use to see this?! :D

Thanks. :D

Anyone???

Hello All... :) Is anyone willing to have a look at a segment/paragraph of my draft narrative and make some comments.??? Please PM me or reply in this thread Thanks in advance. :)

Yup, will do.. Thanks again. :)

Can someone please confirm I need to expand ... Then I should get k?? :)

Good...:D Thanks (again)... So will need to expand out (k + 1)^2 - 4 x 1 x (k+1/4)... This right?

Hello All... :) Could someone please help me with this Q? Q. Find values of k in the equation x^2 + (k + 1)x + (k+1/4) = 0 if: the roots are real. _______ So this means the discriminant is greater than or equal to 0?? Thanks in advance. :)

Yeah thanks... I can substitute b = -1 into product of the roots... A = 0. :)

Hello All. :) Just a quick question.... If the Q was: x^2 + 4x - a = 0; the roots were b+1, b-3; Find the values of a and b I've got b = -1 (Sum of roots = -b/a)... Now, how do I get a? I had it a minute ago but have forgotten.... Thanks for your help in advance. :)

Thanks for your comments... :)

Thanks all for your suggestions. :D

Yeah ok, that sounds good...:) You assumed right!! It is 5 + 30s leeway... That's right, I'm planning for it to land in that range... Hehe... That's true... :D A good point... Will consider that... :) Thanks for your comments.