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I also do think that if you are enjoying chemistry, bio would not be too bad. Yes the content is a lot but it is not mentally taxing to understanding whereas for physics it is competitive if you are in a good school, so bio might be a better fit. Normally i would stan physics but i guess bio...

That is the shell theorem.

Well the question you ask is not particularly well defined but I will help with what I have understood of it. If we consider Earth and Mars as isolated systems and you are on either of them, then you would feel the strongest force when you are in the center of mass of both the planet and...

Well, just hints but: 1) Write the chemical equation. Find the number of moles of each reactant in the reaction using n = m/MM 2) If one is in excess, that means not all of the moles of this excess chemical is used up. (i.e. if AlCl3 is in excess, then only the number of moles of NaOH reacts to...

Well this is true. One way you can think about it is that at 45 degrees, a projectile has a maximum range. So as I deviate further from 45 degrees on either end, the range changes are going to be equivalent. (But really this has to do with a more mathematical reason where the angle is limited...

yep you are right exactly so now what this becomes is a conical pendulum problem. So first i need to know the actual radius to find the exact value for the ω and how would I find this - imagine a conical pendulum: Now its been a while since i've done such problems so im leaving it to you to...

Using, ω = v/r = 3/(0.20) = 15 rad s^-1 but this doesn't match any of the answers... so i think it would be worth checking the source?

Alright so a fairly straightforward apporach to this question: So what I have written below is the solution and no hints so be wary. 17) a) Remember show not equals prove, hence we just need to show that LHS = RHS LHS = x^n - 1 RHS = (x - 1) (x^n-1 + x^n-2 + ... + x^2 + x + 1)...

Well, the first thing you wanna do is simplify the system a bit into something like what my diagram shows: Now this just makes everything clear such that we know the net force is zero. Hence, the force in the vertical direction is zero and the horizontal direction is also zero. Write this as...

Yes libraries are your best friends here. Some other recommendations for getting resources are past papers on the nsw website, ace hsc, thsc and atar notes (as you have said). Finishing all of these along with the textbooks will be more than enough for anyone, especially once the school work...

Well... reading your first post on this thread really did invigorate me. It's been a while since i've experienced/ seen that much passion and I admire it greatly. AIE's a great place and I wish you luck. Not to put a damper or anything but surely being a "ubermensch", you have seen a person...

Hey, so I understand that you need a 99.90 and I didn't come close to it so i dont know if my perspective will help but I wanna give some thoughts. Some important things to remember is that it is not necessary to have as many units under your belt as possible - the goal is to do as well as you...

Well in that case neither are very helpful. Terry lee allows you to deal with the very hardest of the questions of the HSC although is a bit excessive in my opinion. Fitzpatrick 4U is very good for the basics and developing flexible exam technique but not a whole lot of difficult questions. So...

You forgot to include the 0.75x tern in your final quadratic.

Oh damn I though it was gonna be a round robin. Clearly didnt read the rules properly. gg then.

hmm... this has happened to me before and there are some things i religiously follow for any exams, even the ones im doing now so i hope it helps. Well first off, it is important to go into an exam with a calm mind and a clear goal. First off, atleast 3 hrs before the exam do not touch anything...

Well uh have you tried auxiliary angle method where you let: R sin(x + a) = cos(x) + 3sin(x) R = sqrt(3^2+1^2) = sqrt(10) a = cos^-1(1/sqrt(10)) = 1.249 Hence, you can solve the equation: sqrt(10) sin(x+1.249) = 1 And i trust you can do it from here.

Bro it wasn't as serious as yours was but this happened in yr 10 for me. Nearly everyone in all the grades had a full copy of the geography teacher (it was on google forms btw) and it was circulating around. When the teacher found out, he nearly got everyone in the class suspended but when the...

I feel like 2, 7 and 13 were the ones most students would have got correct. 16 seemed like the least likely answer that was answered because it takes a minute realize what the question is even asking (and i don't even know what hartmann's solution is). Nice paper and definitely on the difficult...

That's an excellent paper.. just wanted say because it is much more balanced that last year and has improved greatly. Nice one.