Search results

Thank you so much! That was very helpful. I'll definitely keep in mind all that you've said. A final question: Would you think the best course of action is to overload 6 units of OLE over with in semester 2 and then overload the final 6 in semester 1 of year 2 because it seems hard to overload...

Hello, I'll be studying at the University of Sydney as a first year student this year, and I had a few questions. Firstly, here are my provisional units of study for next year: CHEM1991 MATH1902 MATH1921 PHYS1903 INFO1110 (?) CHEM1992B MATH1905 MATH1923 PHYS1904 INFO1113 (?) So, I'm doing the...

No idea what that is, I'm not all that far beyond HSC maths :(

Really hope I'm right coz this took me forever. Also sorry for bad LaTeX. I=\int_0^{\pi} \mathrm{ln}(1+2a\mathrm{cos}(x)+a^2)\mathrm{d}x \frac{\mathrm{d}I}{\mathrm{d}a} =\int_0^{\pi} \frac{2\mathrm{cos}(x)+2a}{1+2a\mathrm{cos}(x)+a^2}\mathrm{d}x = \frac{1}{a}\int_0^{\pi}...

Jathu shouts me lunch if he doesn't get at least 3 state ranks

Nice, just scored myself some free lunch :)

nah ur getting 99.95

nice joke

mystery mark

Uhh, my school was weird. I did well in math in year 9 so they were like "yeah screw it you and these other three kids can do accelerated 3U" and then me and my other friend decided to do accelerated 4U.

Honestly, sometimes I feel like my genny friends can count to ten better than I can.

Last year in my 3U exam, I read a question wrong. And in my 4U exam, not only did I also read a question wrong, I did 2 x 1 = 1...

127 I read hahaha

Ah unlucky. Everyone make silly errors, don't worry about it haha.

appreciate the support

Correct me if I'm wrong, but here's what I get: Yeah 8 is B which is just by subbing in (-x) into the equation. Then 9 is C. So dy/dt = dy/dt * dt/dx = -x/y * 1/y = -x. Then, consider that in the first quadrant, y is positive so dx/dt is positive, and hence x is increasing. So it seems like it...

Yeah, that was my logic as well, hence why I did negative. But, yeah as you said, I don't see any real reason to deduct marks for neglecting the negatives.

I'm guessing, either I'm wrong in doing the negative, or even if you can technically do a negative they won't care about it. Like, I won't pretend to know all the definitions in conics, so you could totally be right. And in that case doing the negative is wrong.

I'm not sure if they'd require that honestly, a and b are usually assumed to be positive anyway. I just did that for completeness.

Vertices on the y axis don't exist though. Sub in x = 0 and you get y^2 = -b^2 which unless y = b = 0, is impossible, and b=0 can't be the case either. I did forget the other case though which I've fixed up now.