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There is no errors in my solution is there Jetblack?

I use BSc Hydroxyburn Pro (3kg bucket). It's expensive as all shit but god damn it get's results quickly. Read more about it here: BSc Body Science Hydroxy Burn Pro Lean + Ripped Protein Formula::Supplements::Supplements, Boxing Equipment, Martial Arts Equipment, Compressors, MMA Clothing, Gym...

There should be a group dedicated to the haters haha

I think you will be just fine lol I suppose your first everything should be memorable (mine were), after the first, memories just become a blur...oh no wait, that was probably the alcohol

but... aren't you hot as?!! Surely it has been your choice not to be kissed

Yeah i agree, Cambridge 2U is the best in my opinion. Coroneos is great also

[/FONT] [/FONT] Anymore Q let is know :)

hahaha agreed, we share the same passion. What are you gonna be doing at uni bro?

GUSSSSSS...: "never claimed i had any =[[" I am one! I hate that kid lol

I'm one! Most backtracking/retarded post of all time, this was part of the "non uniform circular motion" where he was once again burnt. For more: http://community.boredofstudies.org/14/mathematics-extension-2/220865/non-uniform-circular-motion.html

lol o, i was thinking, that is the most epic thing i have ever heard. Yeah, having a great holiday thanks man, likewise to yourself! Looking forward to uni next year or what?

That is crazy man!!! Good luck to you namu

Type up the Questions and we will ASSIST you, we will not do your homework for you

Yeah, MX2 is just substitution into a set of formulae, theres no need for any thought what so ever, which explains why EVERY student takes it and gets 100 in it.

Label points: Label the square ABCD and uncommon side of triangle as E Well since it's a square so BCD=90 (angles of a square are all <90) Therfore DCE=45 (complimentary angles) But angle CDA=90 (square) therefore EDC=90 (st. line <) So DEC=180-(90+45)=45 (angle sum of triangle) therefore...

Firstly, welcome to BOS. I think that visual demonstrations of applications of calculus (ie. projectile motion, SHM) would be very useful. Even if it is just to help explain the different points within the motion e.g. At max hieght, y'=0. Range=2 x time to reach max hieght and how the vertical...

y^1/2 = 2-x^1/2 y^2=(2-x^1/2)^4= (2)^4+4(2)^3(-x^1/2)+6(2)^2(-x^1/2)^2+4(2)(-x^1/2)^3+(-x^1/2)^4 =16-32x^1/2+24x-8x^3/2+x^2 V=pi int(b-->a) y^2 dx , should be right from there

Ok well: b^1/3=1/7 (b^1/3)^3=(1/7)^3 [cubing both sides] b=1/7^3=1/343 Similarly n^-2=121 (1/n^2)=121 therefore by rearranging n^2=1/121 (n^2-1/121=0, so it's a difference of squares) n= +1/11 or -1/11 Alternatively: If you're looking for quick indice ways n^-2=1/121...

:O! Archman returns! You're Ivan Guo right?

Precisely what tommy said. I wanted to work for a year. 1) to save money, since im moving away for uni, didn't want to find to live really hard for four years 2) Although my parents were willing to pay for alot, i want to be independent and kinda do it on my own as much as i can. 3) I got a...