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Same here, btw I just discovered this forum, here is the proof I quoted to my friend for i) "I did some work on Question 16 c i) x^2 + (y-c)^2 = r^2 And y=x^2 Substitute 2 into 1 y + (y-c)^2= r^2 Rearrange (expand) to make a quadratic, y as the variable y+y^2 -2yc + c^2 -r^2 = 0...

I did some work on Question 16 c i) x^2 + (y-c)^2 = r^2 And y=x^2 Substitute 2 into 1 y + (y-c)^2= r^2 Rearrange (expand) to make a quadratic, y as the variable y+y^2 -2yc + c^2 -r^2 = 0 Grouping terms y^2 + y(1-2c) + (c^2-r^2) = 0 We know that there are two equal (in terms of y)...

Go for geogebra, it's brilliant (aaand also the only one I've used, but brilliant too!).

Very well in the first 15 questions, but gee that question 16 was nasty If anyone could go through a proof of 16(c) I'd be extremely thankful. For those who haven't sat the test, and just want to help out, the question was (I'm not familiar with Latex, sorry): The Circle...