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no radius.

youngminii... just no. k02033 that info is not supplied, so again no, also they are both going anticlockwise. i know how this goes, but only how to acccuratly figure out mars.

lol this is my favorite part of space :P easy formulas= win

waves: frequency and wavelength c=f lambda light has properties prescribed by maxwell, shown by hertz particles: photons --> energy per photon by e=hf intensity is number of photons here photoelectric effect. displacing electrons(einstein)

wait wat????, this is out of a text book you know

a)522* 1/0.9999 b) 7.382748513years c)522* 1/0.9999 CBF

i thought this was a joke lol. wat dumby said :P

um...2/3 is bigger than 1/2 :P

hows this i think this might work.... keplers law of periods= (R^3)/T^2=k if orbiting around same centre(sun)....... using a ruler radius of earths orbit=2.5 mars=4.3 period of earth = 1 so (2.5^3)/1^2 =15.625=(4.3^3/t^2) rearrange to 15.625/(4.3^3)= t^2=0.19652..... sqr root=0.4433

3 years

question is on board of studies. with the given information all i can figure out is that mars has changed position less than 180degrees. i don't think that would cut it. the markoing criteria said 1/3 orbit, where did they get it from?

yeah, i get .75 as well

Can someone show me how they did this? i can't figure it out