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Ok so when I graph this into geogebra: That is: (y-\frac{1}{3}(15-4x))^2=(x-3)^2 You get two straight lines on the same plane, and they satisfy the equidistance between the two lines, if you were to use like perpendicular distance formula or something. Does this mean Im right?

Well they are both part of the same planes arent they? :s So I assume they would have the same y's?..... for x=3, we dont know what y could be, it could be any value and when that varies along with P(x, y), we get equidistant?..

Not necessarily, if Belonging is easier, everyone finds it easier and hence in order to maintain some sort of bell curve, even if you are absolutely right about whatever Belonging it is, if its not deep enough compared to the top of the year people then you are going to get 'scaled' down for it...

Re: MX2 Integration Marathon Lol isnt that what used to say element of? I dont know much about the math notation, I just didnt want to write k is an integer in latex, and wanted it to do it fancily heh. Because from 0 to 2pi we have some parts of the sine function which is less than zero...

Re: MX2 Integration Marathon From the 'ASTC' rule, or rather knowing that the sine graph is positive for: 0 \leq x \leq \pi \ \ 2\pi \leq x \leq 3\pi \ \ \ \ etc So I generalised the statement with k integer. However when I saw from 0 to pi and 0 to 2pi above, I dont mean x, I mean for any...

Just make a rectangle and integrate where you are supposed to: Solution

Re: MX2 Integration Marathon Oops, lol. Hmm.. So the domain is for all x \sin x + \cos x \geq 0 Using auxilliary angles \sqrt{2} \sin (x + \frac{\pi}{4}) \geq 0 So our domain is k\pi \leq x+ \pi/4 \leq (k+1) \pi \\ \\ k\pi - \frac{\pi}{4} \leq x \leq (k+1)\pi -\frac{\pi}{4} \ \ \ \ k...

The exact question: The point P(x, y) is equidistant from the lines: x=3 And 4x+3y-15=0 Find the locus of point P. What I did: Let variable point A vary on x=3 Therefore the coordinates of A are: A(3, y) Let a variable point B vary on the line 4x+3y-15=0 Therefore the coordinates of...

Re: MX2 Integration Marathon \int \sqrt{1+\sin 2x} \ dx \\ \\ = \int \sqrt{\sin^2 x + 2\sin x \cos x + \cos^2 x} \ dx \\ \\ = \int \sqrt{(\sin x + \cos x)^2} \ dx \\ \\ =\int \sin x + \cos x \ dx \\ = \sin x - \cos x +C Also if its possible, could someone when they post their integrals put a...

Yeah you should make a textbook carrot, Im serious

The reason this took so long for me is that I differentiated and tried to go on further when I was differentiating that theta expression, but with x^2 in the denomiantor for some strange reason, I did this about 3 times to check if I did a silly mistake, I then realised I was differentiating...

Any other scrapped 3U questions?

Its this laid back attitude that I can survive on the minimum and that there are many pathways and alot of opportunities in life that prevent people from succeeding. Best have the all or nothing attitude in order for motivation and discipline (whether its true or not) to be able to get into a...

Name: Rank: Around 100s Teachers: Great Resources: Good Performance: Generally 'alright', good maths performance generally. Your Cohort: Better than previous years, better in english and mathematics and everything pretty much, Id expect my cohort to fetch a 70-80 school rank. Overall: 10/10...

Stickying this could be beneficial, before people bump it down with their y12 adventures.

Could you link it to me or post it? Thanks man

The only reason why I chose to find both the negatives and positives, is because my simplification is BOTH negative AND positive. When we square root something, we do \pm And that means we have two paths in a way, a positive path and a negative path, the positive path will lead us to the...

Spiral can you check whether my argument for this question is valid? http://community.boredofstudies.org/showthread.php?t=290553&p=6081159&viewfull=1#post6081159 Thanks

You type it under the tags [.tex] and [./tex] (without the dots) Then you type your code inside of it (or you can copy paste the WYISWG code from the latex generator)

For Extension 2 English Critical Responses, does it have to be about a text/franchise etc. Or can it be something more broad like society, sociology or philosophy or something.