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If you're a Year 12 student who has felt that the first module (Production of Materials) has been difficult or that you feel that you need concepts to be re-taught to you, please feel free to contact me for group tutoring sessions with your friends in Cabramatta during the summer holidays...

*bump* Check, like and follow the Facebook page for more offers (coming in the next few days). If you want to start the Year 12 Chemistry course fresh, a special offer is available for summer holiday classes. Link: https://www.facebook.com/chemistry.tuition

I agree with drogonski's and coffee_'s advice however, if possible, you should also consider learning things in a group setting with your friends if you're comfortable with the idea. For example, you could delegate dot-points and get each other to explain it to each other. By doing that, you...

Iron artefacts are normally stored in highly alkaline solutions (pH>10) so that it prevents further corrosion. This is because the chloride ions present in the iron hydroxy chlorides (e.g. Fe(OH)Cl) can react with water to form HCl and thus a basic medium would be most appropriate as it prevents...

Hi everyone! I'm advertising my services in chemistry tuition to anyone who is interested in improving in Chemistry. I am currently a third year Education/Science student at the University of Sydney. I love Chemistry and Science in general as it helps us have a better understanding of the...

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\begin{align*}y'&=\frac{2x}{x^{2}+e} \\y &= ln{(x^{2}+e)} + C \\ \text{When }x=0\text{ and }y=2, \\2&=ln(0^{2}+e)+C \\2&=ln(e)+C \\2&=1+C \\C&=1\end{align*} \\\therefore {y = ln{(x^{2}+e)} + 1}

\begin{align*}2^{x+1}&=3^{x-1} \\2\times 2^{x}&= \frac{1}{3}\times 3^{x} \\6\times 2^{x}&=3^{x} \\\frac{3^{x}}{2^{x}}&=6 \\ln{\frac{3^{x}}{2^{x}}}&= ln{6} \\ln{3^{x}}-ln{2^{x}}&=ln{6} \\xln3 - xln2 &= ln6 \\x(ln3 -ln2)&=ln6 \\x&=\frac{ln6}{ln3 -ln2} \end{align*} QUESTION: \text{Find }\int...

Ah okay, thanks dude. :)

Oh okay. Could you please suggest any trial exams that are difficult/challenging?

Hey, I was wondering if anyone had digital copies (i.e. PDFs or word documents) of past Sydney Grammar School trials for the 2U course. If so, could you please give me a copy? Thanks in advance.

Helium is a monatomic molecule (i.e. a molecule that consists of one atom only).

Here's a link that might help. Year 8

\begin{align*} {\frac{\mathrm{d} }{\mathrm{d} x}}\left(e^{\sqrt{x}} \right)&= \frac{e^{\sqrt{x}}}{2x^\frac{1}{2}} \\ \int \frac{e^{\sqrt{x}}}{\sqrt{x}}dx &= 2 \int\frac{e^{\sqrt{x}}}{2\sqrt{x}}dx \\ &= 2e^{\sqrt{x}} +C \end{align*}

\begin{align*}\int \frac{e^x + 1}{e^\frac{x}{2} + e^\frac{-x}{2}} dx &= \int \frac{e^x + 1}{e^\frac{x}{2} + \frac{1}{e^\frac{x}{2}}}dx \\ &= \int \frac{e^x + 1}{\left(\frac{e^x + 1}{e^\frac{x}{2}}\right)} dx \\ &= \int \frac{(e^x + 1)(e^\frac{x}{2})}{e^x + 1}dx \\ &= \int e^\frac{x}{2}dx \\ &=...

\begin{align*}f'(x)&=\frac{cosx.(-cosx)-(-sinx)(1-sinx)}{(cosx)^2} \\&=\frac{-cos^2 x-(-sinx+sin^2 x)}{cos^2 x} \\&=\frac{-cos^2 x+sinx-sin^2 x}{cos^2 x} \\&=-\frac{cos^2 x+sin^2 x-sinx}{cos^2 x} \\&=-\frac{cos^2 x+sin^2 x-sinx}{cos^2 x} \\&=-\frac{1-sinx}{cos^2 x} \\&=-\frac{1-sinx}{1 - sin^2...

Chocolate Coffee Rain.

Solutions for some past HSC Mathematics papers: 2005: http://www.itute.com/wp-content/uploads/nsw-bos-mathematics-solutions-2005.pdf 2006: http://www.itute.com/wp-content/uploads/nsw_bos_maths_sol2006.pdf 2007: http://www.itute.com/wp-content/uploads/nsw_bos_maths_sol2007.pdf 2008...

Pm-ed you the number.