Search results

WHY would u base it off something THEY will 100% know is plagiarism?

Thanks for help guys i managed to work it out =]:)

So i know reduction occurs at the cathode and oxidation at the annode but the question says Ni (electrode) is in Ni(NO3)2 aq and Pt (electrode) is in KCl aq (Cl2 gas is being put in) i went to the standard potentials but cant seem to work out which is the annode and which is the cathode? help...

Small error in part (c) Therefore amount needed to release 22643789.474 kJ = (2643789.474)/285 = 9276.454294 moles (the 22643789.474 should be 2643789.474 there was just an extra 2 just a typo =])

is the reason u divide heat of combustion by average molar mass is so u get kj per gram? hey soz haha but im really unsure why in part b you got: heat of combustion= delta H/n =5460 i dont understand how you got this?