Search results

english adv 89 maths ext 1 95 maths ext 2 89 economics 83 studies of religion II 87 Matrix estimate 96.4 :)

hey if anyone is sending out notes it would really be appreciated. my english teacher is a total ignoramous please send to philip_huang93@hotmail.com thanks =D

no like boom said you're integrating with respect to t, hence the 'dt' so t is the variable in this case not theta

emailed! thanks and rep!

LHS%20=%20\tan(\theta%20+\frac{\pi}{4})\tan(\theta-\frac{\pi}{4})%20\\%20=%20(\frac{\tan\theta%20+%20\tan\frac{\pi}{4}}{1-\tan\theta\tan\frac{\pi}{4}})(\frac{\tan\theta%20-%20\tan\frac{\pi}{4}}{1+\tan\theta\tan\frac{\pi}{4}})%20\\%20=%20\frac{\tan^2\theta%20-%201}{1-\tan^2\theta}%20\\%20=%20-\fra...

i have got an english assessment coming up and is extremely desperate for a song that shows us that belonging involves compromise. anyone have any ideas or thoughts or analysis. any help would be great..cheers :D

Given the parabola x2=y/2 , for what values of m does the line y=m(x+1) have two points of intersection? thanks

got it thanks!

Hi guys i need help with this question, Given that , prove that . thanks!

wow just learnt a new method, thanks drongoski !

shoudnt it be 5pi/3 not 5pi/6? edit: whoops too slow.

Ah ok thanks!

Oh ok thanks but for the first question i think you made a mistake, the 4 digits, the first can be 5 7 8 or 9 so its 4x4x3x2 = 96 96+120 = 216 and for question 2, Whered the combination come from? It was 6Pr = 120. i got 6!/(6-r)! = 120 6! = 120(6-r)! 6!/120 = (6-r)! 6 = (6-r)! i...

Hi i need some guidance with these questions. 1. How many numbers greater than 4000 can be formed from the figures 3, 5, 7, 8, 9? (Repetitions are not allowed). 2. If 6Pr = 120 find the value of r. 6!/(6-r)! = 120 ; is there a way to expand the (6-r)! ? 3. Show that nPr = (n-2)Pr + 2r...

yeah... is this all the information that is given?

LITE, Giraffes? Giraffes!, toe

Re: 回复: Trig identitiy simplification 1-sin^2 (180-@) = cos^2 (180-@) = (-cos@)(-cos@) =cos^2 (@)

gah thanks guys, cant believe i couldnt see that >->'

cos(4x) - 7sin^2 (2x) = 0 solve for 0 =< x =< 360 thanks

Prove sin^{6}%5Ctheta%20+%20cos^{6}%5Ctheta%20+%203sin^{2}%5Ctheta%20cos^{2}%5Ctheta%20=%201 Thanks!