Heat 210g of water by 65ºC using ethanol
specific heat capacity= 4.18
heat of combustion of ethanol = 1367KJ/mol
∆H=mc∆t
= 210 x 65 x 4.18
= 57057 J (57.057 KJ)
Since half heat is lost to surroundings, only 683.5 KJ/mol of heat was utilized from the ethanol.
so 57.057/moles of ethanol =...