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the angle with the vertical is the angle that the rain would be making with a line going straight down

so if 8 of the 36 trout were tagged, then 8/36 of the total trout in the dam should be tagged. Therefore 20 is equal to 8/36 of the total number of trout. dividing 20 by 8/36 gives you 90, so b.

complex polynomials graphs integration (just started)

5 periods a fortnight before school we were planning on doing it during 2u but the assistant principal screwed up and made our teacher teach general every time we have 2u :(

Hey guys, can anyone tell me how to start off a speech other than "Today I will be talking to you about..." opinions please :)

Does anyone know any future ways of producing portable electricity through chemical reactions?

I'm still doing complex numbers just started complex polynomials stuff today teacher doesn't really explain, just copies out of his book not sure what book it is he just photocopies it and gives it to us I think it's Fitzpatrick it's got new senior maths: four unit course at the top

english and sor 1 absolutely hate them but they're compulsory sigh...

Which poem does catcher in the rye most relate to in immigrant chronicle? Opinions please

yay... yr 12... anyways signing in subjects in sig. good luck everyone! :)

i enjoy my maths and science. its just english and sor i hate. sigh failing my compulsory subjects

find the gradient of a point within the region then show there are no turning points within that region i.e. the gradient doesnt change

3.a. 0.187 is positive so θ is in the first and 4th quadrant θ = 79.22, -79.22 b. sinθ = -3/4 -3/4 is negative so θ is in the 3rd and 4th quadrant θ = -48.59, -131.41

1. P = [(-1 + 5k)/(k +1) , (7 + 2k)/(k+1)] since it lies on 5x-4y=1 [5(-1+5k)/(k+1)] - [4(7+2k)/(k+1)] = 1 (17k-33)/(k+1) = 1 16k - 32 = 0 k = 2 2. draw the triangle hyp = 5 opp = 2 adj = √21 cos(270 - θ) = -cos(90 - θ) = -sinθ = -0.4 cot(360 - θ) = -cotθ = √21/2

can someon send me an analysis of teh red tree by shaun tan because i can't find one on the net anywhere or just tell me how it relates to belonging

i was just wondering if it was better for my atar if my whole class did well in private assessment like research tasks or in the HSC exams

cross multiply is where u get the bottom of each fraction and move it over to the top of the other fraction. if u still dont get it multiply both sides by (p -j) Q(p-j)/p =s (Qp - Qj)/p = s multiply both sides by p Qp - Qj = sp and u end up with wat i got before

cross multiply and u get Qp - Qj = sp Qj = Qp - sp j = (Qp - sp)/Q

the horizonatal length is x and the vertical length is y. to get y rearrange the eqn to get y = -3x/2 + 3 so the area is x(-3x/2 + 3) A = -3(x^2)/2 + 3x) dA/dx = -3x + 3 stat pts at dA/dx = 0 -3x - 3 = 0 x = 1 d2A/dx2 = -3 --> max pt A = -3/2 + 3 =1.5

can u be more specific about wat u want? did u want to make j the subject? also is j part of the fraction?