Search results

Fortstreet High, what about you? heres the CSSA MX1 2011 Solutions: http://www.4shared.com/document/xUGk3_1Y/2011_Maths3U_TrialHSC_CSSA_Sol.html

the black market, it exists

anyone have the independent MX2 2011 paper, and the CSSA MX2 2011 paper (the link on the MX2 forum isn't working)? Im gonna upload CSSA MX1 2011 solutions soon :)

Hey guys what are the tags needed to display latex? Cheers

Is it legal/allowed for students to bring in the key directive terms, such as analyse/assess/describe into an exam? Or is it not allowed for HSC examinations?

Thanks, got it now

From Independent Trial HSC 2006 Q4 Bob chooses six numbers from the numbers 1 to 4 inclusive. A machine then chooses six numbers at random from the numbers 1 to 40 inclusive. Find the probability that none of Bob's numbers match the numbers chosen by the machine, giving the answer to 2...

Thanks for the tip! Heres how I finally did it :) \arg(z^2-a^2)=\arg(z+a)(z-a)=\arg(z+a)+\arg(z-a)\\arg(z-a)=\left(\frac{\pi-\theta}{2}\right)+\theta=\frac{\pi}{2}+\frac{\theta}{2}\\arg(z+a)=\frac{\theta}{2}\quad\text{as diagonals of rhombus bisect angles in corner}\\\therefore...

\arg(z^2-a^2)=\arg(z+a)(z-a)=\arg(z+a)+\arg(z-a)=\frac{\theta}{2}+\left(\frac{\pi}{3}+\theta\right)\ there is an equilateral triangle created due to the vector of z-a?

Yea, i just printscreened it, so maybe there was a typo. However, I initially mistook it for the difference of two squares and went ahead anyway but still I couldn't get anywhere.

Oops didn't see that. lol

Hey guys I'm stumped on this question, unfortunately there weren't any solutions provided :( Thanks