• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Search results

  1. T

    99.95 | Maths (2,3,4u) Tutoring! | 2 Years Tutoring Experience | Dual State Rank

    Bump! Now that school's been back for a few weeks, it's always a good time to get ahead :D.
  2. T

    99.95 | Maths (2,3,4u) Tutoring! | 2 Years Tutoring Experience | Dual State Rank

    Hi guys! My name is Thomas, but most people call me Tugga (don't ask me why - I have no idea!). I've posted before here, but recently studied abroad at the University of Pennsylvania for a semester, so had to take a break from tutoring for a while! I'm now looking for a few new students to...
  3. T

    99.85 ATAR Maths Tutor

    Can confirm top notch bloke and intelligent individual! Helped me loads throughout high school and during HSC. Would recommend giving him a go :D
  4. T

    State rank | 99.95 hsc tutoring | all rounder band 6 content guaranteed

    bump! Can confirm, very knowledgeable guy and would expect him to be a great teacher!
  5. T

    Hsc 2013 q

    The train is accelerating though :S. When the string is cut the ball drops in a diagonal straight line, (in the frame of reference of train)
  6. T

    Hsc 2013 q

    To the best of my understanding... 1)I'll explain after 2) 2)It is inertia. If there was say a mass on a frictionless surface within the train, it would, in the frame of reference of the train, move backwards. The opposing force that they're talking about is the tension in the string keeping it...
  7. T

    Hsc 2013 q

    I think it's the floor pushing up against the astronaut (providing centripetal force). The reaction pair is then the astronaut pushing back against the floor. This is simulating gravity (him being pushed into the ground). Hope that helps :S
  8. T

    2014 HSC Extension 2 Maths Carrotsticks' Solutions

    I talked about how the ellipse is symmetric around x and y-axis, so the problem can always be transformed into a theta such that 0<=theta<=pi/2. Not sure if it was required/legit though :L
  9. T

    Parramatta Library HSC Chemistry Trial Discussion

    The emitted electron is from a neutron decaying to a proton + electron right?
  10. T

    2014 BOS Trial Extension 1 Exam Results Thread

    Wowowow my privacy carrotsticks :'(. Haha nah just kidding. Thats cool, I was already satisfied with passing anyway :P Yeah, will keep that in mind, was just rushed for time etc. Thanks again!
  11. T

    2014 BOS Trial Extension 1 Exam Results Thread

    I thought I got the projectile one out using auxiliary angle and the fact that arctan(1/x) + arctan (x) =π/2, was this an accepted method and did I just make too many assumptions or something?
  12. T

    2014 BOS Trial Extension 1 Exam Results Thread

    Ohhh because k doesn't have to be an integer right
  13. T

    2014 BOS Trial Extension 1 Exam Results Thread

    How do you do the external interval one?
  14. T

    2014 BOS Trial Extension 2 Exam Results Thread

    I think I got like 1/7 for the graphing questions GGGG, wonder what the marking criteria was
  15. T

    2014 BOS Trial Extension 1 Exam Results Thread

    Did they not accept auxilliary angle method for the projectile in q16? Like converting the sin+cos into a single one to find the max...
  16. T

    (another) past ruse Q .. hmm

    Oh hmm, yeah true! My bad, it would probably be easiest to find the adjacent sides equal then :) (or that the distance from P is the same if that makes it easier algebra-wise)
  17. T

    (another) past ruse Q .. hmm

    The tangents are perpendicular to each other (this is apparent when using point gradient to find their equations). Squares have diagonals that are perpendicular and bisect (I think), so you only need to prove that the midpoint is the same? Also, this midpoint has to be the point P.
  18. T

    HSC 2014 MX2 Marathon (archive)

    Re: HSC 2014 4U Marathon When you sum the product of roots you get this: (gonna try use fancy latex) $Let the non-real, complex roots be $ \alpha, \bar{\alpha}, \beta, \bar{\beta}, \gamma \bar{\gamma} \\ $Then by summing the product of roots from each equation$ \\ \alpha \bar{\alpha} +...
Top