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1) Find the first derivative of y = 3x² - 2x - 4, which is y' = 6x - 2
2) Re-arrange the line 2x - 3y + 7 = 0 into y = mx + b so I can find the gradient 'm' which is 2/3
3) Since for perpendicular m1.m2 = - 1, thus (6x - 2)x(2/3) = - 1
4) Multiplying them, (12x - 4)/(3) = - 1
5) 12x - 4 =...