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There are 1.6x10^-3 moles of HCl and 1.5x10^-3 moles of NaOH. Therefore NaOH is the limiting reagant and after neutralisation of all the NaOH, there is still 1x10^-4 moles of HCl. This is in 50mL of solution so the concentration of HCl is 2x10^-3. And now use the pH calculation thingo to get: 2.7

Excellent thread

0 for section 2. But what did you write? As long as you wrote something related to a story, you won't get a non-serious

English Advanced - 13/39 General Maths - 5/61 Modern History - 12/25 Physics - 20/23 Legal studies - 1/18 SOR 2 - 13/17 School rank is something like 150 I'm aiming for an 82 ATAR to beat my brother. Do I have a chance?

I'm sure my teacher is more than qualified thank you very muchh! If she's an idiot then you solve it!

Maybe?

You sure??? Y would my teacher give me it then? I think you are overcomplicating it. I just want to find x, y, and z!

I got x=-3 y=-4 z=1/5 But i dont think its right :S

My teacher gave us this question for homework, she said she wanted to challenge us. x+y+z=4 x-2y-17z=56 I don't get it :S

I would say definitely over 95. Your ranks are pretty good, maintain them and gun your externals then you're all set. Do you know what the dux of your school usually gets? Just as an idea.

This thread title does not make sense at all. If you mean "better" in terms of scaling wise, then 2U would trump General over most cases. How much do you value your ATAR?

Silence is golden.

Perhaps this thread will interest you. http://community.boredofstudies.org/showthread.php?t=258521

I remember a user on BOS that had got about 97 ATAR estimate from his school, ended up getting 99.7 Anything can happen as long as you put in enough work.