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97.50 c:

Can you upload the short answer questions, please?

Best of luck everyone! :)

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Answers?

+1'd. :)

Since f'(2)=0, there is a stationary point when x=2. Since f'(x)>0 for x<2, the gradient is positive for any x-value less than 2 (so that it slopes to the right). Since f'(x)<0 when x>2, the gradient is negative for any x-value greater than 2 (so that is slopes to the left). Sketching this...

Goodluck everyone! :)

Re: Tutor for Eng adv(96), math2u (97) Rate? Can you teach at Liverpool Library?

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You can use the quotient rule. y'= (u'v - uv')/ v^2 Therefore, y'= 0(x-3) - 1(5) / (x-3)^2 ∆ y'= -5/(x-3)^2

Anwar English Advanced Chemistry Physics MX1 MX2 (I hope so) Legal Studies SOR1 :)

Thanks guys :)

How do you guys manage procrastination? Any tips?

Well done on your excellent marks and ranks. Keep up the good work for externals and you should be up there. What do you wanna do at uni?