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  1. cookiez69

    jnney bby how u -ayscebby

    jnney bby how u -ayscebby
  2. cookiez69

    Semester 2 USYD Chatter Thread 2013

    When I walked onto campus early this week and found those trees cut down, it took a part of my soul away man. They've been with me through good and bad times. Now what trees shall I weep on during finals week? (I am well aware there are others, but those were irreplaceable) Only time will...
  3. cookiez69

    Semester 2 USYD Chatter Thread 2013

    So I'm not the only one who felt sad about the eastern ave trees that got cut down :D yay! I especially miss the tree next to the bubbler in front of the chemistry building labs. eh, they'll be back.......when i've moved on from uni lyf... :cry:
  4. cookiez69

    Semester 2 USYD Chatter Thread 2013

    I wish there were more courses like ATHK1001. Thanks for the recommendations - HPSC1000 LOOKS AMAZING!
  5. cookiez69

    Semester 2 USYD Chatter Thread 2013

    Hey guys, it's Aysce (on my brother's account). For those of you who have done ATHK1001 (Analytical thinking), could you please offer some opinions? I'm planning to take it but I also need to do another elective that is useful to me and will also enable me to maximise my WAM. WRIT1001 is...
  6. cookiez69

    Roll Call: Class of 2014

    Hey guys :D I'm doing MX1, MX2, physics, chemistry, economics and english advanced. Despite what I say in my sig, my atar aim is 98+ (One year left to go, LETS DO THIS)
  7. cookiez69

    Locus Question

    D: y = -3/4 Sub y = -3/4 into the equation of the line PF. 3x + 4(-3/4) - 3 = 0 3x - 6 = 0 x = 2 Therefore R(2,-3/4)
  8. cookiez69

    Circle as a locus

    Got it, thanks!
  9. cookiez69

    Locus Question

    a = 3/4 units F(0, 3/4) m = (3-3/4) / (-3-0) m = -3/4 Sub into the point gradient formula y - 3 = -3/4 . (x+3) 4y-12 = -3x - 9 3x + 4y - 3 = 0
  10. cookiez69

    Circle as a locus

    Find the exact length of the tangent from (4,-5) to the circle x^2 + 4x + y^2 - 2y - 11 = 0 Thanks :)
  11. cookiez69

    Trig

    Yeah, it didn't give me a particular form. I chose my own one, but only one specific form worked. I must've done something wrong so I'll go back and redo the working out.
  12. cookiez69

    Trig

    Hey guys so I'm a bit confused on something. So here's two separate questions: $Solve for 0^{\circ} \leq x \leq 360^{\circ} $ \\ 4sin\theta - cos\theta =-3\\ and\\ sin\theta -cos\theta =1\\ So i've tried using the transformation method, and I've expressed the first question in the form...
  13. cookiez69

    Complex Numbers

    Thank you very much!
  14. cookiez69

    Complex Numbers

    Hey guys, I'm confused for both questions a) and b) Thanks in advance :)
  15. cookiez69

    Differentiation (with co-ordinates) :):):)

    1) dy/dx = -6/x^2 (Gradient of the tangent at any particular x-value) Finding the equation of the tangent: y-3=(-6/x^2)(x-0) Since we need to find the point of intersection, sub in y=6/x 6/x - 3 = -6/x 12/x = 3 12=3x x=4 (This is your 'a') sub into y=6/x y=6/4 = 3/2 Therefore P(3, 3/2) 2)...
  16. cookiez69

    Coordinate Geometry question.

    Ohhh I did this method and I see where I went wrong now, thanks so much!
  17. cookiez69

    Coordinate Geometry question.

    Hey guys, Q: Find the coordinates of the centre of the circle that passes through points (7,2), (2,3) and (-4,-1). Thank you :)
  18. cookiez69

    Help? Past exam question?

    i) 104 degrees. This is because the diagonals of a rhombus bisect the angles and therefore 52 + 52 = 104. ii) 76 degrees. Opposite angles in a rhombus are equal. 180 - 104 = 76 degrees.
  19. cookiez69

    Bearing Question

    Here you go, if you don't understand some of my working out tell me.
  20. cookiez69

    Help Differentiate?

    y=(3x+5)^6 . (x)^\frac{1}{2} . All you do is use the product rule and when you differentiate for u' and v', you must use the product rule as well. Try it for yourself first, but if you need the working out tell me.
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