ive been able to successfully solve for q(t) where w=2root5 but do we need to resolve both c1 and c2 constants? my final answer for d) was q(t)=c1*cos(2root5*t)+c2*sin(2root5*t)-5root5*t*cos(2root5*t) which i believe is right. My lecturer is the chinese one so her english isnt very good - i...
yeh im in the 3rd lecture stream atm doing the assignment. i was getting the 100sin(2root5t)=0 as well but still not convinced why its Atcos(2root5t)+Btsin(2root5t)