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Assume, without loss of generality (because you can switch a and b and the expression would still be the same) a = 1 + i b = 1 - i (worked out by quadratic formula) x + 1 = cot theta sub a, b, x+1 basically everything into LHS expression and simplify

thats completely fine! im happy you liked it, although i didnt manage to pull off this answer during the actual exam so it really is a shame. The time- limit is a complete bummer to conceptual questions :c

Not really much of an error, but just an inquiry about Q16 bii Let DE = x DE/BC = BF/BC = 1/root2 (because BF/BC = FG/CA = 1/root2 by corresponding sides of similar triangles in same ratio) therefore, DE = BF = x and so BC = root2 x FC = BC - BF = (root2 - 1)x ZE = FC = (root2 - 1)x...

thanks, although the paper this year was easier so it might seem we did well, but really we didn't haha

So basically, i just have to pretend that the first few questions are really easy, skip them and spend all my time trying to do the last question to be a 'beast'... right?