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The graph i have above, in red is y=-sqrt1+sqrt(1+x)the green is y=x and the blue one is y=x^4-2x^2. Regardless of whether there are two branches in the graph given, the original function only exists if x>-1, and in order for the inverse graph to show symmetry about y=x, the x<-1 is the inverse...

I think that q10 is only 1 meeting point or A , terry lee is suggesting B