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I just found it. (Mind you, it's been like 5 years since my HSC and I was just going off the top of my head and, as it seems, my memory turned out to be quite correct) https://www.dropbox.com/sh/ytcsnu1tmskklhv/AACS0G0bzY03FUu3iYCOJ0UPa

Lol Q13c is basically copied from a Victorian paper ... Q12c is very similar to a past HSC paper (2004 I think) I've seen Q14a previously. Other questions seem pretty standard as well. Seems very unlike a typical Ruse paper. Perhaps the person writing it couldn't be bothered with...

Didn't see this until now. I'm quite sure it is written in LaTeX. You can get packages which change the font to 'Times' (but not 'Times New Roman' because it's proprietary or something).

That's a bit contradictory in itself ... usually when one refers to a "prediction", they are referring to something outside the data points to which the data was fitted. Anything inside would be the "fitted value" of the model ...

Yes, but note what was said in the marker's comments for Q2(c)(ii) of the 2005 Extension 1 HSC paper: "Some candidates tried to use integration by parts to do this question. However, very few were successful using this method."

The syllabus has been the same since 1981 with minor modifications in 1990...

I think the HSC paper is written in LaTeX even ...

I meant complex maps. I still think there's serious question as to whether it is in the syllabus or not. Anyway, isn't mapping curves -> curves the same thing as mapping points -> points? I.e. In the former case aren't we mapping the points of a curve to another point of a curve etc? Oo

Lol, they have colour now. And I see now reason why the papers would be retained given that they wouldn't be reusing the questions.

I don't think Q11(c) is really in the syllabus because it involves mappings (although it can be done by arguments/circle geom as well). I think, in fact, the syllabus explicitly excludes these types of locus questions.

A lie is still a lie. Perhaps "no real solution" would've been more appropriate.

Lies. Let x = a+ib (where a and b are real) Then e^(a)e^(ib)=-1 e^a (cos b + i sin b) = -1 Equate real and imaginary parts: cos b = - e^(-a) and sin b = 0 So b = π and -1 = -e^(-a) e^a = 1 a = 0 Thus, x = iπ is also a solution.

Re: HSC 2013 4U Marathon It's worth noting that these types are not in the 4U syllabus. Still interesting though.

I could make a joke about this, but I shalln't. But yeah, hyponatrimia could be an issue...

Re: HSC 2013 4U Marathon This can also be proved using mappings in complex numbers/analysis.

Re: HSC 2013 4U Marathon Lol, a bit of 1st year micro economics...

Which question was that?

In my opinion, that's the way it should be... If there is massive aligning then it means the exam was too hard, and that's stupid because they should set a doable exam which separates the cohort out without aligning.

Perhaps they're trying to lower the actuarial drop out rate...

Usually when a class is 'full' then it is. They might open up new spot though. What do you mean?