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    Maths Question

    Here is how you do it guys: 3^t x 9^(t+1) = 1/3 3^t x 3^2(t+1) = 1/3 because 3^2 = 9 3^(3t+2) = 1/3 Now use the log rules In3^(3t+2) = In(1/3) (3t+2)In3 = In(1/3) 3t+2 = In(1/3)/In3 3t = (In(1/3)/In3)-2 t = ((In(1/3)/In3)-2)/3 Now sub into calculator t = -1
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