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how do you study for maths? i dont.

hahah 20 questions right in section 1 :P

awwww Da, better find that missing one! :D

88200 ways i wrote out all the combinations took me some time i could scan it for you, but that will be like over 50 pages

UNSW maths comps have nothing to do with 4U and 3U. It really depends whether your interests and ability lies in maths - if you think you can handle 3U pretty easily then take up 4U. If you're in it for the "scaling" then forget about it - you probably won't do well in 4U. I got like 98% or...

get stuck on first question, sit there and stare at paper, get stuck stuck, continue sitting there for 2hrs, then move onto next paper and get stuck again.....etc, until your 40hours is up :P

i just did the CSSA 2004 paper (for practice) and it didnt really seem that hard :P well not as tricky as the ones before

hmm Bob.J why say one degree after another when i can do two at the same time :P yeah i know alot of people do finance/actl, but doing a stat may seem to diverse my paths slightly (well a little more:))....maths seems like something thats not REALLY applicable when you go out and get a career...

hey everyone im in yr12 atm and am planning to do a double degree with Acturial and BSci maj in stat, but im wondering if the two subjects would overlap? I am also deciding whether to do BCom Actu /BSci Stat or BCom double maj Actu and finance because I would think finance would be more...

note AKIN. not THE ANSWER IS perhaps we should close this thread now, we're not getting anywhere

http://www.boredofstudies.org/community/showpost.php?p=842200&postcount=4 crashoveride already posted it

which one? the one you posted or rt (tanx)?

hahaha dh yeah wot a noob he got me and ngai to do it :P

yeah what a cheater :@ next they'll ask how to integrate rt (tanx)....though thats do-able

no worries ;)

multiply by cis @, where @ is your degrees of rotation anticlockwise rotating by 90deg anticlockwise is equivalent to multiplying by cis(pi/2) = i ; clockwise is cis(-pi/2) = -i therefore to rotate by pi/3, multiply by cis(pi/3)

pfffft trying to be a smartass

guess you left out Q29 ngai :P join up centres of circles (*) join from centre of top circle to meet line joining bottom circle's centres => it is perpendicular as the lines in (*) form a equilateral triangle altitude of triangle = rt ((2+2)^2 - 2^2) = rt12 (by pythagoras) therefore P to...

:mad: takes my credit too haha

(i)x = -p +/- rt(p^2 - q) = -p +/- rt(q-p^2)i (since p^2 - q <0) now, arg (H) - arg (K) = pi/2 but arg (H) = -arg(K) (since H is conj of K) => 2arg (H) = pi/2 => arg (H) = pi/4 => rt (q-p^2) / -p = 1 => q-p^2 = p^2 => 2p^2 - q = 0 as required (ii) H. K = q => |H||K| = |q|...