Well, good question, it will give a similar graph to f(x)=1/(x^2+x) but not the same. However, it is not about asymptote. In f(x)=(x-1)/(x^3-x), x cannot =1, so the function is discontinuous at the point (1, 1/2), however, in f(x) =1/(x^2+x), the curve will include the point (1, 1/2). Apart from...