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Heard so many victim cases. But not sure why they are still around :mad:

Xmas soon.

I'd love to help you, but I need to go to a Xmas party now. Can I attend those questions for you later?

(1) the parabola cuts x-axis at x=2, 3 ((x-2)(x-3) = 0). The gradient of tangents is m = 2x-5, so m1=-1, m2 = 1. So equation1: y = -x + 2 and equation2 y = x - 3. They meet at (5/2, -1/2) since -x + 2 = x - 3 => x = 5/2, and y therefore is -1/2 from any of these two equations. (2) f'(x) =...

Anyone interested? You can check with my current and past students if you'd like.

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b) gradient of OP = y/x, gradient AP = y/(x-5) c) gradient of OP x gradient of AP = -1 => (y/x) * (y/(x-5)) = -1 => x^2 -5x + y^2 = 0 => circle d) (x- 5/2)^2 + y^2 = (5/2)^2 => center = (5/2, 0), radius = 5/2

bump, bump, bump

DO you need a reliable and quality tutor in this area (covering from Casula, Liverpool, Wattle Grove, Holsworthy, Moorebank, Chipping Norton, Bankstown, to Hurstville etc.) ? I tutor math to all levels (yes, to 4U and Uni.), Physics, English to YR10 only.