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remeber RED CAT, so reduction occurs at teh cathode. This means that an ion is gaining electrons and depending on the ion in question may stay in solution but lower in oxidisation number, be reduced to a solid which forms on the cathode itself, or be reduce to a gas which floats away into...

no way guys, droolian has the most explosive method of study this side of canickledook. To quote ernest hemingway "Droolian is a fascinating example of social darwinism run amok, truly a beutiful human being". If i were Jarrod, i would kindly return to my seat and replace the tray in it's...

hey guys, our clas just recieved an assesment task for this option. We are supposed to perform expreiments in our own time, detirmine experimental procedure, theory, results etc. The two experiments in question are syllabus reference: 9.6.2.1b - compare the rate of corrosion of iron...

hey gronktron, go to vinnies and get yourself an old man jumper and stop whining you pussy who frickin cares so much about a jumper and who would pay $500 for some stupid monkey shirt

i see

how did you find the derivative of cosec (x) and the integral of cosec^2 (x)? ive always been puzzled, what is the derivative of sec x, and cosec x

how did you find the derivative of cosec (x) and the integral of cosec^2 (x)

ok in this example, why in part 3 do they substitute their value into the result from part 2 and not the original polynomial

actually i dont get it i can only get as far as the first step via binomial expansion, but where do the angles come in? ..... riviet?

dont worry i got it

use de movre's theorem to express cos 4θ in terms of cos θ and use your results to solve the equation 8x^4 - 8x^2 + 1 = 0. hence show that: cos π/8 + cos5π/8 + cos 7π/8 = 0 cos π/8 . cos 3π/8 . cos 5π/8 . cos 7π/8 = 1/8 (π is supposed to be pi)

happy?

is it too big, how much smaller would you liek it, to the nearest ratio divisible by e^6 and then express in polar for and perform a trig substitution on it while looking atthe screen upside down

our teacher said that we only have to know it qualitatively and the momentum calculations are not part of the syllabus, but screw that lets do it anyway

strong induction, eh? ill give it a go, is that part of 4 unit syllabus by the way?

ok so your saying the modulii of both sides is equal, fine i get that. byt isnt the modulus of lhs: sqrt[ (x^2 - y^2)^2 + (2xy)^2 ] owing to the fact that (x + iy)^2 = x^2 - y^2 +2xyi

complex numbers, polynomials, integration, graphs, harder 3 unit circle geometry and induciton, mainley cos for term 4 last year after hsc we had about 5 ext 2 classes a week owing tothe fact the whole class is the accelerants who did their hsc last year, and wd already covered 2 and 3...

wow thats so helpful, i just dropped a bit of cheese as i read it ! i tried multiplying it out and gave up cos it is some massive numberthat will simplify out really well but it looked to huge to continue

can anyone do question four - see attatchment (i scanned the whole thing so that i can refer to other questions if need be, and if anyone feels like some maths)

well ive been here for ages, just didntget an account till hsc year when i really needed it