3U MATHS HELP (1 Viewer)

[J2good4u]

In velocity and acceleration if given v^2= 2(x^2-3x-4) where v=0 and x=4
How to Show that the particle does not pass through the origin.

 

[bleakarcher]

v^2=2(x^2-3x-4)
When x=0:
=>v^2=2[0^2-3(0)-4]=-8
But in order for motion to exist v^2 must be greater than or equal to 0.
Therefore, the particle does not pass through origin x=0.

 

[J2good4u]

thanks