• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

another co-ord geo qs (1 Viewer)

Smeegen999

***********
Joined
Mar 2, 2007
Messages
143
Location
Your house
Gender
Female
HSC
2008
find the acute angle between the straight lines with equations

3x - y = 5

2x - 4y + 1 = 0

thanks!!!
 

Mark576

Feel good ...
Joined
Jul 6, 2006
Messages
515
Gender
Male
HSC
2008
tan Θ = |m1-m2|/|1+m1m2|, where Θ is the angle between two lines with gradients m1 and m2.
 
Last edited:

me121

Premium Member
Joined
Apr 19, 2006
Messages
1,407
Location
-33.917188, 151.232890
Gender
Male
HSC
2007
well this works by calculating the angle each line makes with zero degrees. i.e. the line horizontal from the origin.

So if you change the form,
3x - y = 5
into
y = 3x -5
i.e. gradient is 3.

and for the second one,
2x - 4y + 1 = 0
4y=2x+1
y=1/2 x + 1/4
i.e. gradient is 1/2.

Now we know that tan-1 gradient = angle the line makes with the +x axis.

so to calculate the angle between the lines we can subtract the angle of one of the lines with the angle of the other line. if this gives a negative answer, change the order of the terms. however there will always be two angles, you can calculate the other one by using 180 - angle.

this is how you would derive the formula. and as a side note, even for my hsc, i never memorised the formula, i just used the above method.

EDIT: This is a 3unit topic. You will not be examined on it in 2U. By the looks of your profile, you only do 2U.
 
Last edited:

Mark576

Feel good ...
Joined
Jul 6, 2006
Messages
515
Gender
Male
HSC
2008
3x - y = 5 => m1 = 3
2x - 4y + 1 = 0 => m2 = 1/2
∴ tan Θ = |3-(1/2)|/|1+(3/2)| = 1
Θ = tan-11 = 45o

Does that help?
 

Smeegen999

***********
Joined
Mar 2, 2007
Messages
143
Location
Your house
Gender
Female
HSC
2008
me121 said:
well this works by calculating the angle each line makes with zero degrees. i.e. the line horizontal from the origin.

So if you change the form,
3x - y = 5
into
y = 3x -5
i.e. gradient is 3.

and for the second one,
2x - 4y + 1 = 0
4y=2x+1
y=1/2 x + 1/4
i.e. gradient is 1/2.

Now we know that tan-1 gradient = angle the line makes with the +x axis.

so to calculate the angle between the lines we can subtract the angle of one of the lines with the angle of the other line. if this gives a negative answer, change the order of the terms. however there will always be two angles, you can calculate the other one by using 180 - angle.

this is how you would derive the formula. and as a side note, even for my hsc, i never memorised the formula, i just used the above method.

EDIT: This is a 3unit topic. You will not be examined on it in 2U. By the looks of your profile, you only do 2U.

oh i see, its a 3 unit topic - that explains it! I was stressing out majorly because I've never seen that formula b4 lol. thanks 4 clearing that up. That qs was in my stupid 2U textbook! :)
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top