T Teoh Member Joined Feb 8, 2004 Messages 150 Jun 15, 2004 #1 Umm... Proof: (1+x)<sup>n</sup>(1+1/x)<sup>n</sup> =1/x<sup>n</sup> (1+x)<sup>2n</sup>
wogboy Terminator Joined Sep 2, 2002 Messages 653 Location Sydney Gender Male HSC 2002 Jun 15, 2004 #2 LHS = (1+x)^n * (1+1/x)^n = ((1+x)(1 + 1/x))^n = (1 + 1/x + x + 1)^n = (x + 2 + 1/x)^n = 1/x^n * (x^2 + 2x + 1)^n = 1/x^n * ((x+1)^2)^n = 1/x^n * (x+1)^2n = RHS
LHS = (1+x)^n * (1+1/x)^n = ((1+x)(1 + 1/x))^n = (1 + 1/x + x + 1)^n = (x + 2 + 1/x)^n = 1/x^n * (x^2 + 2x + 1)^n = 1/x^n * ((x+1)^2)^n = 1/x^n * (x+1)^2n = RHS
