Binomial Probability - Percentages (Help) (1 Viewer)

Heresy · Nov 18, 2018

"The probability of a certain brand of light globe being faulty is 1.3%. In a batch of 8 such light globes, find the probability, as a percentage correct to 1 decimal place, that none will be faulty"

HeroWise · Nov 18, 2018

In this question it is imperative to understand binomial prob itself
$Let us say, P(Faulty)= 0.013 whilst P(Not Faulty)=1-P(Faulty)=0.987$
$$so $\binom{8}{0}(0.013)^0(0.987)^8 =0.9006109466$

Now simply convert it to a percentage which would be $90.1\%$(One decimal places)$$

Heresy · Nov 18, 2018

HeroWise said:
In this question it is imperative to understand binomial prob itself
$Let us say, P(Faulty)= 0.013 whilst P(Not Faulty)=1-P(Faulty)=0.987$
$$so $\binom{8}{0}(0.013)^0(0.987)^8 =0.9006109466$

Now simply convert it to a percentage which would be $90.1\%$(One decimal places)$$

My mistake. I found 1.3% of 8 and worked with those probabilities - lol kms.

Binomial Probability - Percentages (Help) (1 Viewer)

Heresy

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HeroWise

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Heresy

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