J jordon1 New Member Joined May 23, 2013 Messages 1 Gender Male HSC 2014 Jul 2, 2014 #1 Been trying to work this one out for ages found it in a old HSC test 2lnx = ln(4x+5) and the answer is x = 5 can anyone reveal how this is to be done
Been trying to work this one out for ages found it in a old HSC test 2lnx = ln(4x+5) and the answer is x = 5 can anyone reveal how this is to be done
Squar3root realest nigga Joined Jun 10, 2012 Messages 4,883 Location ya mum gay Gender Male HSC 2025 Uni Grad 2024 Jul 2, 2014 #2 ln(x^2) = ln(4x +5) x^2 = 4x + 5 x = -1 or x = 5 domain(ln) > 0 hence x = 5 was not a challenge and my mind is the same consistency as before i solved it
ln(x^2) = ln(4x +5) x^2 = 4x + 5 x = -1 or x = 5 domain(ln) > 0 hence x = 5 was not a challenge and my mind is the same consistency as before i solved it