complex no. (1 Viewer)

=)(= · Nov 10, 2022

Am i high or is ab a rotation of oa by 2pi/3 anticlockwise?

carrotsss · Nov 10, 2022

i may be wrong but I don’t think there’s enough info to determine that?

Never mind I am silly

Drongoski · Nov 10, 2022

What's the question?

Lith_30 · Nov 10, 2022

=)(= said:
View attachment 36993
Am i high or is ab a rotation of oa by 2pi/3 anticlockwise?

Yeah cause for triangle AOC is congruent to triangle ABC, so angle DAB is 60 degrees too.

=)(= · Nov 10, 2022

Drongoski said:
What's the question?

They want us to find oc in terms of w given oa=w

Drongoski · Nov 10, 2022

I think $\overrightarrow {OC} = \sqrt 3 i\omega$

OBC is an equilateral triangle

$\angle AOC \text { is right-angled and }\overrightarrow {OC} \text { is therefore a multiple of } i\omega; \text { indeed: } \sqrt 3 i\omega \\ \\ \text {since: }OC = \sqrt 3 \times OA $ as $ tan\frac {\pi}{3} = \sqrt 3 \text { and } i \text { rotates }\omega, $ $\frac {\pi}{2} \text { anticlockwise along OC}.$

By the way: OABC is a kite

=)(= · Nov 10, 2022

complex no. (1 Viewer)

=)(=

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carrotsss

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Drongoski

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Lith_30

o_o

=)(=

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Drongoski

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