Complex number question??? (1 Viewer)

[Michaelmoo]

Solve the following equation:

x^2 - 2isec[theata]x - 1 = 0

Im getting x = i(sec[theata] + Tan[theata]) and x = i(sec[theata] - Tan[theatre]).

Is this right? Or is there a way to simplify it even further???

Thanks.

 

[independantz]

Are you missing an x, otherwise it should simply be
x=+/-(2isec(theta)+1)^1/2

 

[Zeber]

first of all, its THETA, not theatre.

if you're missing an x in the isec@, then use quadratic formula
otherwise do what ndependantz said.

 

[x.Exhaust.x]

Are you missing an x, otherwise it should simply be
x=+/-(2isec(theta)+1)^1/2

Any working? I still don't get it.

 

[independantz]

Any working? I still don't get it.

x^2-2isec(theta)-1=0
x^2=2isec(theta)+1, take the thing to the other side of the eq
x=+/- (2isec(theta)+1)^1/2 , square root both sides.

 

[x.Exhaust.x]

x^2-2isec(theta)-1=0
x^2=2isec(theta)+1, take the thing to the other side of the eq
x=+/- (2isec(theta)+1)^1/2 , square root both sides.

Thanks .