xV1P3R
Member
- Joined
- Jan 1, 2007
- Messages
- 199
- Gender
- Male
- HSC
- 2010
Hi, I found this question in a textbook and was wondering how you
would divide x³-2-2i by x+1-i
The answer is
x³-2-2i = (x+1-i)[x²+(-1+i)x-2i]
I've tried turning it into a fraction and realizing the denominator, but end up with something horrible. I suppose you could manually alter the numbers so they factorize nicely, but I was wondering if there was an easier way.
Thanks
would divide x³-2-2i by x+1-i
The answer is
x³-2-2i = (x+1-i)[x²+(-1+i)x-2i]
I've tried turning it into a fraction and realizing the denominator, but end up with something horrible. I suppose you could manually alter the numbers so they factorize nicely, but I was wondering if there was an easier way.
Thanks