hmm i thought that bit was always going to be hard to convey on a forum. sorry about that.bos1234 said:why do you have to do this?
to cancel out the -2 in front of the dx multiply the integral by -1/2
thanks for thius tipelseany said:when the numerator is a degree lower than the denominator you should instantly consider logs. the trick with these questions is that you need to get the top looking like the derivative of the bottom, if you can recognise that and manipulate the top you can skip the process of substitution.
so in this question to get the top looking like the derivative of the bottom you gotta multiply by -2, so to balance this you need to multiply by a -1/2 outside the integral.