do we consider the negative sign for lenz's law with graph problems??? (1 Viewer)

anonymoushehe

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I got A which is what the answer said, but i was just a bit iffy cause I approached the question by considering the fact that the gradient gives the rate of change in magnetic flux, and since there is only one coil, N =1. So the induced emf would be -gradient of the curve. I graphed out the derivative of the original graph, and flipped it about the x axis, but none of the answers matched except for the first one which was not flipped about the x axis? So do we just ignore the negative sign of the induced emf equation or?
 

wizzkids

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The sign in Lenz's Law is not decisive in this question.
Look more closely at the diagram.
  • The current is measured by a galvanometer in series with the circuit.
  • The polarity of the galvanometer is not shown on the diagram.
  • Therefore, the direction of the current through the loop is not absolutely defined.
  • Select the graph that shows two current impulses with opposite directions, i.e. (A)
 
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anonymoushehe

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The sign in Lenz's Law is not decisive in this question.
Look more closely at the diagram.
  • The current is measured by a galvanometer in series with the circuit.
  • The polarity of the galvanometer is not shown on the diagram.
  • Therefore, the direction of the current through the loop is not absolutely defined.
  • Select the graph that shows two current impulses with opposite directions, i.e. (A)
oh so can you define whatever direction as positive for current?
 

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