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Experiment Help! >.<// (1 Viewer)

mecramarathon

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What experiment could you carry out in the laboratory to determine the solubility of copper II sulfate in grams per 100 mL of water using room temperature, 50 c and 80 c ?
 

hosay

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Well, simply you need to determine how much of it dissolves in the water.

A simple way to do it would be to place 100mL of water in a beaker and then heat to 50degrees or 80degrees (whatever one you are testing for). Now Weigh out about 10g of Copper Sulfate and add it to the water and stir. If it all dissolves, add another 10g and keep doing this until no more dissolves and you have a precipitate of Copper Sulfate.

Now, to determine how much copper sulfate dissolved, u need to weigh what didn't dissolve (the precipitate) and subtract it from the total amount of Copper Sulfate you put in.

An easy way to do this would be to use filter paper, but if you want to be more accurate, use a porous ceramic crucible (ask teacher).

Remember not to cool the water before filtering, cause you want to determine volubility at Ur set temperature, and solubility is temperature dependent.

In summary, solubility (g/100mL)= total mass of Copper Sulfate added-Weight of dried precipitate
 
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