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LHS=1/(p^2+pq) + 1/(q^2+pq)Finx said:2. i) Show that 1/(p^2+pq) + 1/(q^2+pq) = 1/pq
I figured this one out, but for the next bit:
ii) Hence express 1/5 in the form 1/a + 1/b for some positive integers a and b.
What the hell does this mean? >_<
1/(p^2+pq) + 1/(q^2+pq) = 1/pqFinx said:2. i) Show that 1/(p^2+pq) + 1/(q^2+pq) = 1/pq
I figured this one out, but for the next bit:
ii) Hence express 1/5 in the form 1/a + 1/b for some positive integers a and b.
What the hell does this mean? >_<
LHS:shaon0 said:LHS=1/(p^2+pq) + 1/(q^2+pq)
=q^2+2pq+p^2/(q^2+pq)(p^2+pq)
=(p+q)^2/q(p+q)*p(p+q)
=(p+q)^2/pq(p+q)
=(p+q)/pq...
What is your solution for the first part?
Ah I see, p=5 and q=1 (for the positive factors of 5), then after subbing etc you get the 1/30 and 1/6. Sweet, thanks =D1/(p^2+pq) + 1/(q^2+pq) = 1/pq
1/5 = 1/(5 x 1)
= 1/(5^2 + 5 x 1) + 1/(1^2 + 5 x 1) = 1/30 + 1/6
Therefore, a = 30 and b=6 as bored of sc said.
Oh...okayFinx said:LHS:
= 1/p(p+q) + 1/q(p+q)
After multiplying by q/q and p/p respectively
= q/pq(p+q) + p/pq(p+q)
= (p+q)/pq(p+q)
= 1/(p+q)
Ah I see, p=5 and q=1 (for the positive factors of 5), then after subbing etc you get the 1/30 and 1/6. Sweet, thanks =D