help how is it A (1 Viewer)

[anonymoushehe]

I got B?? I solved it by working out the domains and ranges for each separate function and then added the max and min values of each interval?

 

[Hehehe22]

You can't do that because the min and max y values aren't at the same x value. You can see this if you graph it

 

[anonymoushehe]

You can't do that because the min and max y values aren't at the same x value. You can see this if you graph it
View attachment 47367

OHHH YEAHHHHH MAKES SENSE NOW THANKS

 

[zzz5428]

A more reliable way to do this is using the identity: arcsinx + arccosx = pi/2. This is pretty well known and can easily be proved. The method mentioned above is unreasonable as you cannot assume that applies to all x in the domain even though it does.

 

[anonymoushehe]

A more reliable way to do this is using the identity: arcsinx + arccosx = pi/2. This is pretty well known and can easily be proved. The method mentioned above is unreasonable as you cannot assume that applies to all x in the domain even though it does.

OHHHH thats also very smart thank youu

 

[NotBamboo]

I legit just chucked the max and min of the domain into the calculator and sees if theres a math error (C and D) or an answer (got 180 so 1 radian)
this won't work for other questions but we haven't even learnt inverse sin graphs yet